Wire 1 resistor per LED indicator parallel with the LED indicator (see
http://www.ledtronics.com/ds/aut1157m/ for example). That should cure everything and make the rear blinkers appear the same as the front from the relay's point of view.
So if one stock indicator was 21W and the Rizoma is R W, then the load on the relay per side was 42W and:
(42W - R W - LED W) / 12V = Y amps
12V / Y amps = X ohms
The X is the size of the resistor you need to have with one LED blinker in order to have the equal amount of resistance on one side of the relay as there was with the stock bulbs. I would get the kind with the heatsink and mount them attached to the frame as they will get hot.
I did not quite follow your point about adding the integrator to further complicate things. I am sure Rizoma W+integrator W+LED indicator W is still not the same as original 21+21W. You still have only two LED devices replacing one bulb and as a LED blinker usually is 1-2W you are still 17-19W short per side? No?
[ This message was edited by: Martin_R on 2006-04-27 14:31 ]