Triumphrat

razman

[QUOTE=Mr.Pete;2433671]


"38 degrees is about the maximum safe advance.35 degrees (rotor mark 0.075" right of pointer),is a little safer and less likely to cause detonation."

razman

Mr. Pete....earlier in your first post you indicated i needed to move the mark .075" to RIGHT of the pointer to achieve 35 degrees BTDC...now you are saying the opposite, so i am confused. since the rotor rotates counter clockwise, a mark to the right of the pointer would indicate that the bike is firing sooner, or even more advanced......so now moving the mark to the left of the pointer makes more sense to me. (i think, LOL) can you clarify which is correct for me? thanks again for your help, Rick

Mr.Pete

You don't need to put any new mark.
Let's say the original rotor mark is accurate at 38 degrees when it lines up with the pointer.
3 degrees later (only 35 degrees BTDC),the rotor mark will have moved 0.075" past the pointer.The rotor mark will then be to the RIGHT,or counter-clockwise,of the pointer.

razman

ok, (sorry to be so dense) but are you now saying that by putting a mark .075" to the right of the factory rotor mark (which is what i did) and then strobe it, that i should be at 35 degrees? (in other words, the way i described doing it last night should be correct?)

thanks again for all your help, sorry to be such a pain on this thread...Rick

Mr.Pete

Your new mark lines up with the pointer before the standard mark does,with normal direction of rotation.It lines up 3 degrees earlier (more advanced) than the standard mark.38 + 3 = 41 degrees BTDC (not what you want).

When the standard mark has passed the pointer and is 0.075" counter-clockwise and to the right of the pointer,you will be at 35 degrees BTDC.

razman

ok, cool! that all makes perfect sense to me, so i need to make a new mark .075" left of the factory rotor mark, and when they line up i will be (in theory) at 35 degrees BTDC, thanks again, Rick